Maximum torque experienced by an electric dipole is τmax=PEsin90∘.
So, ∣τ∣max=PE
The ratio is τ2τ1=P2E2P1E1=2⋅4×10−30×15×1041.2×10−30×5×104=61
Hence, the value of x=6.
JEE Main 2022 — Physics Electromagnetism
Two electric dipoles of dipole moments 1.2×10−30cm and 2.4×10−30cm are placed in two difference uniform electric fields of strengths 5×104NC−1 and 15×104NC−1 respectively. The ratio of maximum torque experienced by the electric dipoles will be x1. The value of x is _____ .
Held on 28 Jul 2022 · Verified 6 Jul 2026.
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