The current in the galvanometer is calculated by i=(NABK)θ.
Therefore, the sensitivity of the galvanometer,
didθ=KNAB
Hence, only options B and D are correct.
JEE Main 2022 — Physics Electromagnetism
The current sensitivity of a galvanometer can be increased by :
(A) decreasing the number of turns
(B) increasing the magnetic field
(C) decreasing the area of the coil
(D) decreasing the torsional constant of the spring
Choose the most appropriate answer from the options given below :
Held on 28 Jul 2022 · Verified 6 Jul 2026.
(B) and (C) only
(C) and (D) only
(A) and (C) only
(B) and (D) only
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