Using Amperes circuital law: B × 2πr = μ₀I. Therefore B = μ₀I/(2πr)
JEE Main 2022 — Physics Electromagnetism
Verified 30 May 2026.
Question
The magnetic field at a distance r from a long straight wire carrying current I is:
Options
- Aμ₀I/(2πr)
- Bμ₀I/(4πr)
- Cμ₀I/(2πr²)
- Dμ₀I/(4πr²)
Solution
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Electromagnetism in other years
More JEE Main Electromagnetism Questions
A long straight wire carries a current of 10 A. The magnetic field at a distance of 0.1 m from the wire is:
A charged particle moves in a uniform magnetic field. If the velocity is perpendicular to the field, the path of the particle is:
The magnitude of force on a charge q moving with velocity v in a magnetic field B at angle θ is:
The electrostatic force between two point charges q₁ and q₂ separated by distance r is given by Coulomb's law as:
The magnetic field at the center of a circular coil of radius R carrying current I is