Since the voltage across the inductor and capacitor is same, the circuit is in resonance. Therefore, the current in the circuit will be,
i=RV=5220=44A.
The voltage across the inductor is double that across the resistor. Therefore, VL=2VR=440V.
We know that VL=iXL=i×2πfL⇒L=44×100π440=10π1H=π100mH
Therefore, K=1001=0.01≈0.
