
This is a Wheatstone circuit. For the current to be zero in 10Ω the Wheatstone circuit should be balanced. Therefore,
3R=64⇒R=2Ω
Now, the equivalent resistance across the battery will be,
Req=(2+4)+(3+6)(2+4)×(3+6)=3.6Ω
Therefore, the current measured by the ammeter is i=RV=3.636=10A.
