Electric power is given by P=RV2, here, V is voltage and R is resistance.
Now, for each bulb, R1=PV2=1002202=484Ω and R2=PV2=602202=484(610)Ω
Net current through the series combination is I=484+484×610220A=0.171A
Hence, the power consumed by the 100W bulb is P1=I2R1=14.06W