
Each pair on the right side of the circuit is in parallel connection, hence it can be replaced by a resistance of 2r as shown.

Now, r&\frac{r}{2} in each branch on the right side is in series, hence combined resistance value will be, 23r. Upper branch having resistance 23r is in parallel with another 23r, hence it can be written as 43r.

Further, simplified circuit will have net resistance of 87r.

Therefore, Req=87r+r=87+1=815Ω
Now, current I=8153=58A
Hence, value of a=8.
