The frequency given is 0.5 kilo cycle per second ⇒f=500Hz⇒ω=2πf=1000πrads−1.
Total capacitance of the wire is C=0.01×10−6×100F.
Impedance is minimum at resonance. Therefore, for minimum impedance
XL=XC
⇒ωL=ωC1⇒L=ω2C1=10002×π2×0.01×10−6×1001=10−1H=100mH