
Let a current, I pass through the square loop of side, L. The magnetic field at the centre O,
B=4×Magneticfieldduetoeachside
⇒B=4×4πμ0⋅L/2I(sin45∘+sin45∘)
⇒B=πL2μ0I(21+21)=πL22μ0I
Magnetic flux linked with the small square loop,
ϕ=BA=Bl2=πL22μ0Il2
Mutual inductance of the coil,
M=Iϕ=πL22μ0l2.