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A slab of dielectric constant K has the same crosssectional area as the plates of a parallel plate capacitor and thickness 3 4d, where d is the…

JEE Main 2022 — Physics Electromagnetism

2022mcqhard

A slab of dielectric constant KKK has the same crosssectional area as the plates of a parallel plate capacitor and thickness 34d\frac{3}{4}d43​d, where ddd is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be :

(Given C0={C}_{0}=C0​= capacitance of capacitor with air as medium between plates.)

Official previous-year question

Held on 28 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    4KC03+K\frac{4K{C}_{0}}{3+K}3+K4KC0​​

  2. B

    3KC03+K\frac{3K{C}_{0}}{3+K}3+K3KC0​​

  3. C

    3+K4KC0\frac{3+K}{4K{C}_{0}}4KC0​3+K​

  4. D

    K4+K\frac{K}{4+K}4+KK​

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