Force experienced by a particle with charge q in an electric field F=qE.
Now, the acceleration produced is given as a=mF=mqE=1×10−440×10−6×105
=4×104ms−2 (As the particle is projected against the electric field, hence it is decelerated)
Using, v2=u2−2as
We have, 02=u2−2as
s=2av2=2×4×104(200)2=0.5m