Given here, length l=1m, current i=1A, area A=2×10−6m and resistivity ρ=1.7×10−8Ωm.
Resistance of wire is R=Aρl=2×10−51.7×10−8×1=21.7×10−2Ω
Now, electric field in the wire is E=ρJ, where, J=Ai is current density.
Thus, E=Aiρ=iR=1×21.7×10−2Vm−1
Electric force in terms of electric field is given by F=qE
Therefore, force experienced by moving electron is F=1.6×10−19×21.7×10−2
=1.36×10−21=136×10−23N