
Let G be resistance of galvanometer and I′ be the current passing through the galvanometer produces full scale deflection. If I is the maximum current, and since, G and S are in parallel so, the potential difference between them will be same.
Then,
I′G=I2S⇒72I′=8I2⇒I2=9I′⇒I=I′+I2=10I′
So the percentage of total current passes through galvanometer is
II′×100=10I′I′×100=10