
Heat produced in resistor when direct current flows is H1=i2R1t
H1=42(3)t=16(3)t
Heat produced in resistor when alternating current flows is H2=irms2R2tirms=2i0
H2=2i02R2t
H2=242×(2)t=16t
Thus, the ratio is H1:H2=3:1
A direct current of 4A and an alternating current of peak value 4A flow through resistance of 3Ω and 2Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :
Held on 27 Jul 2022 · Verified 6 Jul 2026.
3:2
3:1
3:4
4:3
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