Given circuit is R−L growth circuit

The current is the circuit is given by,
i=RE(1−e−τt)
For current to be half of the peak value,
i=2RE=RE(1−e−τt)
Solving t=τln2
t=RLln2=10010.693=0.00693≃7ms
At time t=15ms,
i(15ms)=RE(1−e−1015)
⇒i=1006(1−41)=43×1006=0.045A
⇒U=21Li2
by solving we get U=1mJ.