Given, N=1000,A=1m2and B=0.07T
The maximum emf generated is ϵmax=NBAω,
=NBA(2πf)
=1000×0.07×1×2π(1)=140π
Thus, maximum emf is 439.6V≈440V.
JEE Main 2022 — Physics Electromagnetism
A circular coil of 1000 turns each with area 1m2 is rotated about its vertical diameter at the rate of one revolution per second in a uniform horizontal magnetic field of 0.07T. The maximum voltage generation will be _____ V.
Held on 24 Jun 2022 · Verified 6 Jul 2026.
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