The initial charge on the 5μF capacitor will be q=CV=150μC. If the charge on the 10μF capacitor is q after the key is closed then,

5150−q=10q⇒q=100μC
JEE Main 2022 — Physics Electromagnetism
A capacitor C1 of capacitance 5μF is charged to a potential of 30V using a battery. The battery is then removed and the charged capacitor is connected to an uncharged capacitor C2 of capacitance 10μF as shown in figure. When the switch is closed charge flows between the capacitors. At equilibrium, the charge on the capacitor C2 is _____ μC.

Held on 28 Jun 2022 · Verified 6 Jul 2026.
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