Given, Ey=900sin(ωt−cωx)
Here, E0=900

Electric field and electric force are related as FE=qE0
Magnetic force of a moving charge is given by FB=qvB0
Thus, the ratio FBFE=vB0E0
Using relation between magnetic and electric field, we have
FBFE=vc=3×1073×108=10:1