
From the given information,
C=d∈0A=2×10−3ϵ0×1F
∴XC=ωC1=2×50π×∈02×10−3=25×4π∈02×10−3Ω
∴XC=252×10−3×9×109=2518×106Ω
∴i0=XCV0=1820×25×10−6A=27.47μA.
The value of amplitude of displacement current will be same as value of amplitude of conventional current.
Hence option 3.