
Charge should be placed near −5μC at x distance

(5+x)2K(20)Q=X2K(5)Q
4x2=(5+x)2
4x2=25+x2+10x
3x2−10x−25=0 ⇒x=5
Two particles A and B having charges 20μC and −5μC respectively are held fixed with a separation of 5cm At what position a third charged particle should be placed so that it does not experience a net electric force ?

Held on 31 Aug 2021 · Verified 6 Jul 2026.
At 5cm from −5μC on the right side
At 5cm from 20μC on the left side of system
At 1.25cm from −5μC between two charges
At midpoint between two charges
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