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The electric field in a region is given by E= 2 5 E_0 i+ 3 5 E_0 j with E_0=4.0× 10^3NC^-1. The flux of this field through a rectangular surface,…

JEE Main 2021 — Physics Electromagnetism

2021integereasy

The electric field in a region is given by E⃗=25E0i^+35E0j^\vec{E}=\frac{2}{5}{E}_{0}\hat{i}+\frac{3}{5}{E}_{0}\hat{j}E=52​E0​i^+53​E0​j^​ with E0=4.0×103NC−1.{E}_{0}=4.0\times {10}^{3}N{C}^{-1}.E0​=4.0×103NC−1. The flux of this field through a rectangular surface, area 0.4m20.4{m}^{2}0.4m2 parallel to the Y−ZY-ZY−Z plane is _______ Nm2C−1N{m}^{2}{C}^{-1}Nm2C−1.

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Held on 17 Mar 2021 · Verified 6 Jul 2026.

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