The above circuit in the question is arranged like that, so all the resistance are connected in parallel and the net resistance of the parallel resistor becomes,

RP1=R11+R21+R31+R41=41+61+121+81⇒RP=3048Ω

Now the net resistance will be, Rnet=(3048+0.6)Ω, so the net power, P=RV2=2.2(2.2)2=2.2W