
Ceq=C1+C2+C3C2C3
Ceq=2dAϵ0+dK1Aϵ0+dK2Aϵ0dK1Aϵ0×dK2Aϵ0
Ceq=2dAϵ0+dAϵ0(K1+K2K1K2)=dAϵ0(21+K1+K2K1K2)
JEE Main 2021 — Physics Electromagnetism
A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K1 and K2 of same area 2A and thickness 2d are inserted in the space between the plates. The capacitance of the capacitor will be given by :

Held on 26 Aug 2021 · Verified 6 Jul 2026.
dϵ0A(21+K1+K2K1K2)
dϵ0A(21+K1K22(K1+K2))
dϵ0A(21+K1K2K1+K2)
dϵ0A(21+2(K1+K2)K1K2)
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