
Taking an element of width dx at a distance x(x<d/2) from left plate
dc=dx(ϵ0+kx)A
Capacitance of half of the capacitor
C1=∫0d/2dc1=A1∫0d/2ϵ0+kxdx
C1=kA1ln(ϵ0ϵ0+kd/2)
Capacitance of second half will be same
Ceq=2C=2ln(2ϵ02ϵ0+kd)kA