B1=4πRμ0I(2sin60)=4π.(233)×10−24π×10−7×1.5×2×23=1×10−5
Bnet=3B1=3×10−5T⊗
JEE Main 2021 — Physics Electromagnetism
A current of 1.5A is flowing through a triangle, of side 9cm each. The magnetic field at the centroid of the triangle is :
(Assume that the current is flowing in the clockwise direction.)
Held on 31 Aug 2021 · Verified 6 Jul 2026.
23×10−5T, inside the plane of triangle
23×10−7T, outside the plane of triangle
3×10−7T, outside the plane of triangle
3×10−5T, inside the plane of triangle
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