B1×2πx=a2μ0I0(x)2
B2×2πx=μ0I0
B2B1=a2x2
JEE Main 2021 — Physics Electromagnetism
A coaxial cable consists of an inner wire of radius a surrounded by an outer shell of inner and outer radii b and c respectively. The inner wire carries an electric current i0 which is distributed uniformly across cross-sectional area. The outer shell carries an equal current in opposite direction and distributed uniformly. What will be the ratio of the magnetic field at a distance x from the axis when (i) x<a and (ii) a<x<b ?
Held on 27 Aug 2021 · Verified 6 Jul 2026.
x2a2
x2b2−a2
b2−a2x2
a2x2
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