At steady state current through branch of capacitor is zero. Potential difference across capacitor is 2V. So, q=50×2=100μC

i=(2+2+2)×1036=1×10−3Amp
VA,B= potential across 50μF
VA,B=i×2×103=1×10−3×2×103=2 volt
Charge on 50μF
q=CV=50×10−6×2⇒100×10−6C=100μC