The electric fields of two plane electromagnetic plane waves in vacuum are given by E_1=E_0 j cos(ω t-kx) and E_2=E_0 k cos(ω t-ky) At t=0, a…
JEE Main 2020 — Physics Electromagnetism
2020mcqhard
The electric fields of two plane electromagnetic plane waves in vacuum are given by E1=E0j^cos(ωt−kx) and E2=E0k^cos(ωt−ky) At t=0, a particle of charge q is at origin with a velocity v=08cj^ ( c is the speed of light in vaccum). The instantaneous force experienced by the particle is:
Official previous-year question
Held on 9 Jan 2020 · Verified 6 Jul 2026.
Options
A
E0q(0.8i^−j^+0.4k^)
B
E0q(0.4i^−3j^+0.8k^)
C
E0q(−0.8i^+j^+k^)
D
E0q(0.8i^+j^+0.2k^)
Did you get this right?
Sign in to track your attempts and accuracy.
Solution
Magnetic field vectors associated with this electromagnetic wave are given by
B1=cE0k^cos(kx−ωt) & B2=cE0i^cos(ky−ωt)
F=qE+q(V×B)
=q(E1+E2)+q(V×(B1+B2))
By putting the value of {\vec{E}}_{1},{\vec{E}}_{2},{\vec{B}}_{1}&{\vec{B}}_{2}