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An electric dipole of moment =(- i-3 j+2 k)× 10^-29 C m at the origin (0,0,0) . The electric field due to this dipole at =+ i+3 j+5 k (note that · =0…

JEE Main 2020 — Physics Electromagnetism

2020mcqmedium

An electric dipole of moment p⃗=(−i^−3j^+2k^)×10−29C m\vec{\text{p}}=(-\hat{i}-3\hat{j}+2\hat{k})\times {10}^{-29}\text{C m}p​=(−i^−3j^​+2k^)×10−29C m at the origin (0,0,0)(0,0,0)(0,0,0) . The electric field due to this dipole at r⃗=+i^+3j^+5k^\vec{\text{r}}=+\hat{i}+3\hat{j}+5\hat{k}r=+i^+3j^​+5k^ (note that r⃗⋅p⃗=0\vec{r}\cdot \vec{p}=0r⋅p​=0 ) is parallel to:

Official previous-year question

Held on 9 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    (+i^−3j^−2k^)(+\hat{i}-3\hat{j}-2\hat{k})(+i^−3j^​−2k^)

  2. B

    (−i^+3j^−2k^)(-\hat{i}+3\hat{j}-2\hat{k})(−i^+3j^​−2k^)

  3. C

    (+i^+3j^−2k^)(+\hat{i}+3\hat{j}-2\hat{k})(+i^+3j^​−2k^)

  4. D

    (−i^−3j^+2k^)(-\hat{i}-3\hat{j}+2\hat{k})(−i^−3j^​+2k^)

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