Given,
Current in the arc A is i1=2A
Current in the arc B is i2=3A
Radius of arc A is R1=2cm
Radius of arc B is R2=4cm
Magnetic field at the centre of circular current carrying arc is given by
BC=4πRμ0i(θ)...(1)
Where, θ is the angle subtended at centre.
Magnetic field at the centre due to arc A and B is given by
BA=4πR1μ0i1(2π−2π)...(2)
BB=4πR2μ0i2(2π−3π)...(3)
Dividing equation (2) by (1), we get
⇒BBBA=i2i1×R1(2π−3π)R2(2π−2π)
⇒BBBA=32×24×23π×5π3
⇒BBBA=56