Acceleration produced by electric field,
a=mqE0i^
After time t, velocity of the particle,
v=u+at
⇒v=v0j^+(mqE0t)i^[∵u=v=v0j^]
So, speed of the particle,
∣v∣=v02+(mqE0t)2
Now, given ∣v∣=2v0after time t, so
2v0=v02+(mqE0t)2
⇒4v02=v02+(mqE0t)2
⇒3v02=(mqE0t)2
So, time interval, t=qE03mv0
Here, we must note that no change in magnitude of velocity is caused by a perpendicular magnetic field. So, we are not taking effect of magnetic field while calculating change in speed.