Given,
Emf of the battery, E=3V
Potential difference across resister R is VR=2.5V
Power dissipation in the resister is P=0.5W
By using Kirchhoff's voltage law is given by,
Vr+VR=E...(1)
Vr is voltage across internal resister.
Using equation (1) and substitute the given values,
⇒Vr+2.5=3
⇒Vr=0.5
Now the ratio of potential across R and r is given by,
VrVR=IrIR=0.52.5=5
⇒rR=5
Now the power dissipation across the internal resistance is given by
PrPR=I2rI2R=rR
⇒PrPR=5
⇒Pr=5PR
⇒Pr=50.5=0.1W