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Two point charges q_1(√10 μ C) and q_2(-25 μ C) are placed on the x -axis at x=1 m and x=4 m respectively. The electric field ( in V/m) at a point…

JEE Main 2019 — Physics Electromagnetism

2019mcqhard

Two point charges q1(10μC){q}_{1}(\sqrt{10} \mu C)q1​(10​μC) and q2(−25μC){q}_{2}(-25 \mu C)q2​(−25μC) are placed on the xxx -axis at x=1mx=1 mx=1m and x=4mx=4 mx=4m respectively. The electric field (inV/m)(\text{in} V/m)(inV/m) at a point y=3my=3 my=3m on yyy-axis is,

[Take14πϵ0=9×109Nm2C−2][\text{Take}\frac{1}{4\pi {\epsilon }_{0}}=9\times {10}^{9} N{m}^{2}{C}^{-2}][Take4πϵ0​1​=9×109Nm2C−2]

Official previous-year question

Held on 9 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    (−81i^+81j^)×102(-81 \hat{i}+81 \hat{j})\times {10}^{2}(−81i^+81j^​)×102

  2. B

    (81i^−81j^)×102(81 \hat{i}-81 \hat{j})\times {10}^{2}(81i^−81j^​)×102

  3. C

    (−63i^+27j^)×102(-63 \hat{i}+27 \hat{j})\times {10}^{2}(−63i^+27j^​)×102

  4. D

    (63i^−27j^)×102(63\hat{i}-27\hat{j})\times {10}^{2}(63i^−27j^​)×102

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