BX=2(4πμ0)d/2M along x -axis
BY=4πμ0(d/2)(2M) along y -axis
BX=BY
Hence Bnet will be at 45o from x -axis.
Now, velocity and magnetic field are in same direction. Hence no force will act on the particle.
JEE Main 2019 — Physics Electromagnetism
Two magnetic dipoles X and Y are placed at a separation d , with their axes perpendicular to each other. The dipole moment of Y is twice that of X . A particle of charge q is passing through their mid-point P , at angle θ=45o with the horizontal line, as shown in figure. What would be the magnitude of force on the particle at that instant? ( d is much larger than the dimension of the dipole)

Held on 8 Apr 2019 · Verified 6 Jul 2026.
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2(4πμ0)(2d)3M×qv
(4πμ0)(2d)3M×qv
(4πμ0)(2d)32M×qv
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