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Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d . The space between the plates of…

JEE Main 2019 — Physics Electromagnetism

2019mcqhard

Two identical parallel plate capacitors, of capacitance CCC each, have plates of area A,A,A, separated by a distance ddd . The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K1,K2{K}_{1}, {K}_{2}K1​,K2​ and K3{K}_{3}K3​ . The first capaciitor is filled as shown in figure I,I,I, and the second one is filled as shown in figure II.II.II.

If these two modified capacitors are charged by the same potential VVV , the ratio of the energy stored in the two, would be (E1({E}_{1}(E1​ refers to capacitor (I)(I)(I) and E2{E}_{2}E2​ to capacitor (II)(II)(II) ):

JEE Main 2019 Physics, Capacitance — question figure

Official previous-year question

Held on 12 Apr 2019 · Verified 6 Jul 2026.

Options

  1. A

    E1E2=9K1K2K3(K1K2K3)(K2K3+K3K1K1+K1K2)\frac{{E}_{1}}{{E}_{2}}=\frac{9K{}_{1}K{}_{2}K{}_{3}}{(K{}_{1}K{}_{2}K{}_{3})(K{}_{2}K{}_{3} + K{}_{3}K{}_{1}K{}_{1}+K{}_{1}K{}_{2})}E2​E1​​=(K1​K2​K3​)(K2​K3​+K3​K1​K1​+K1​K2​)9K1​K2​K3​​

  2. B

    E1E2=(K1K2K3)(K2K3+K3K1K1+K1K2)K1K2K3\frac{{E}_{1}}{{E}_{2}}=\frac{(K{}_{1}K{}_{2}K{}_{3})(K{}_{2}K{}_{3} + K{}_{3}K{}_{1}K{}_{1}+K{}_{1}K{}_{2})}{{K}_{1}{K}_{2}{K}_{3}}E2​E1​​=K1​K2​K3​(K1​K2​K3​)(K2​K3​+K3​K1​K1​+K1​K2​)​

  3. C

    E1E2=(K1K2K3)(K2K3+K3K1K1+K1K2)9K1K2K3\frac{{E}_{1}}{{E}_{2}}=\frac{(K{}_{1}K{}_{2}K{}_{3})(K{}_{2}K{}_{3} + K{}_{3}K{}_{1}K{}_{1}+K{}_{1}K{}_{2})}{9{K}_{1}{K}_{2}{K}_{3}}E2​E1​​=9K1​K2​K3​(K1​K2​K3​)(K2​K3​+K3​K1​K1​+K1​K2​)​

  4. D

    E1E2=K1K2K3(K1K2K3)(K2K3+K3K1K1+K1K2)\frac{{E}_{1}}{{E}_{2}}=\frac{{K}_{1}{K}_{2}{K}_{3}}{(K{}_{1}K{}_{2}K{}_{3})(K{}_{2}K{}_{3} + K{}_{3}K{}_{1}K{}_{1}+K{}_{1}K{}_{2})}E2​E1​​=(K1​K2​K3​)(K2​K3​+K3​K1​K1​+K1​K2​)K1​K2​K3​​

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