
For net force on charge placed at origin is given as
⇒(2d)2KQ.q+d2KQ2=0, where K is a constant.
Solving the above equation, we get, q=4−Q
Hence, the charge q=−4Q such that net force on the charge +Q placed at origin is zero.
JEE Main 2019 — Physics Electromagnetism
Three charges +Q,q,+Q are placed respectively, at distance, 0,d/2 and d from the origin, on the x -axis. If the net force experienced by +Q, placed at x=0, is zero, then value of q is:
Held on 9 Jan 2019 · Verified 6 Jul 2026.
+Q/2
+Q/4
−Q/4
−Q/2
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