GivenI1=−0.3A,I4=0.8A,I5=0.4A,inseriesconnectioncurrentwillbesame,henceI5=I6=0.4A,Accordingtokirchoff′sjuncionrule,algebraicsumofthecurrentsmeetingattthejuctioniszero.i.ecurrentsflowingintothejunctionistakenaspositiveandcurrentflowingoutofthejunctionistakenasnegative.AtthejunctionR,−I4+I2+I1=0⇒−0.8+I2−0.3=0⇒I2=1.1AAtjunctionQ,I6+I3−I2−I1=0⇒0.4+I3−1.1+0.3=0⇒I3=1.1−0.7=0.4AIt is problem of kirchhof's current law.
I6=0.4A
I3=0.8A−O.4A=0.4A
I2=(0.8+0.3)A=1.1A