Resultant force on the charged particle =Fnet =qE+q(V×B)=(2qi^+3qj^)+q(v×B) Also q(V×B)=0 So, required work done W=Fnet⋅S=(2qi^+3qj^)⋅(i^+j^)=2q+3q=5q
A particle of mass m and charge q is in an electric and magnetic field given by overrightarrow E=2 i+3 j ; overrightarrow B=4 j+6 k The charged…
JEE Main 2019 — Physics Electromagnetism
A particle of mass m and charge q is in an electric and magnetic field given by E=2i^+3j^;B=4j^+6k^ The charged particle is shifted from the origin to the point P(x=1;y=1) along a straight path. The magnitude of the total work done is :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
(0.35)q
- B
5q
- C
(2.5) q
- D
(0.15)q
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