C=d∈0A
C1=3dK1∈0A=3K1C
C2=3K2C
C3=3K3C
Ceq=KeqC=3C(K1+K2+K3)
Keq=3K1+K2+K3=336=12
JEE Main 2019 — Physics Electromagnetism
A parallel plate capacitor is of area 6cm2 and a separation 3mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constant K1=10,K2=12 and K3=14. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be:

Held on 10 Jan 2019 · Verified 6 Jul 2026.
4
36
14
12
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