As total length L of the wire will remain constant L=(3a)N(N= total turns ) and length of winding =(d)N 
(d = diameter of wire) self inductance =μ0n2 Aℓ=μ0n2(43a2)dN∝a2 N∝a[ as N=L/3a⇒N∝a1] Now 'a' increased to ' 3a ' So self inductance will become 3 times