m=magnetic dipole moment=IA. For Loop1, m=Iπr2, B1=2rμ0i
For Loop2. If current is constant m is doubled. r1=2r. B2=22rμ0i.B2B1=2
JEE Main 2018 — Physics Electromagnetism
The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B1 . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B2 . The ratio B2B1 is:
Held on 8 Apr 2018 · Verified 6 Jul 2026.
21
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