
ba=100−ll
a+b=1000
ab=110−ll−10
l100−l=110−ll−10
l2−10l=11000+l2
−100l=110l
200l=11000
l=2110=55
4555=ba
⇒a=550Ωb=450Ω
JEE Main 2018 — Physics Electromagnetism
On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10cm. The resistance of their series combination is 1kΩ . How much was the resistance on the left slot before interchanging the resistances?
Held on 8 Apr 2018 · Verified 6 Jul 2026.
910Ω
990Ω
505Ω
550Ω
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