For a balanced meter bridge, 39.5X=(100−39.5)Y⇒Y=39.5=X×(100−39.5)or…X=60.512.5×39.5=8.16Ω When X and Y are interchanged l1 and (100 −l1 ) will also interchange so, l2=60.5 cm
JEE Main 2018 — Physics Electromagnetism
In a meter bridge, as shown in the figure, it is given that resistance Y=12.5Ω and that the balance is obtained at a distance 39.5 cm from end A (by jockey J). After interchanging the resistances X and Y, a new balance point is found at a distance l2 from end A. What are the values of X and l2 ? 
Held on 15 Apr 2018 · Verified 6 Jul 2026.
19.15Ω and 39.5 cm
8.16Ω and 60.5 cm
19.15Ω and 60.5 cm
8.16Ω and 39.5 cm
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