An ideal capacitor of capacitance 0.2μ F is charged to a potential difference of 10V. The charging battery is then disconnected. The capacitor is…
JEE Main 2018 — Physics Electromagnetism
2018mcqhard
An ideal capacitor of capacitance 0.2μF is charged to a potential difference of 10V. The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5mH. The current at a time when the potential difference across the capacitor is 5V is:
Official previous-year question
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
A
0.15A
B
0.17A
C
0.34A
D
0.25A
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Solution
The energy stored in the capacitor is given by, Uc=21CV2. The energy stored in the inductor is given by. UL=21LI2. In LC circuit there is no loss of energy in the form of heat so, using energy conservation, Uci+ULi=Ucf+ULf