Here, side of the triangle, l=4.5×10−2 m, current, I=1 A magnetic field at the centre of the triangle ' O ' B= ? From figure, tan60∘=3=2d1 ⇒d=23l=(234.5×10−2)m 
Magnetic field, B=4πdμ0i(cosθ1+cosθ2) Putting value of μ=4π×10−7 and θ1 and θ2 we will get net magenetic field =3×B=4×10−5 Wb/m2