Rate of heat i.e., Power developed in the wire =P=RV2 Resistance of the wire of length, L R1=AρL=πr2ρL ∴ Power, P1=R1V2 Resistance of the wire when length is halved i.e., L/2 R2=π(2r)2ρ2L=π8r2ρL=8R1 ∴ Power, P2=8R1V=R18V or, P2=8P1 i.e., power increased 8 times of previous or original wire.