Rate of heat i.e., Power developed in the wire =P=RV2 Resistance of the wire of length, L R1=AρL=πr2ρL ∴ Power, P1=R1V2 Resistance of the wire when length is halved i.e., L/2 R2=π(2r)2ρ2L=π8r2ρL=8R1 ∴ Power, P2=8R1V=R18V or, P2=8P1 i.e., power increased 8 times of previous or original wire.
A constant voltage is applied between two ends of a metallic wire. If the length is halved and the radius of the wire is doubled, the rate of heat…
JEE Main 2018 — Physics Electromagnetism
A constant voltage is applied between two ends of a metallic wire. If the length is halved and the radius of the wire is doubled, the rate of heat developed in the wire will be:
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
Increased 8 times
- B
Doubled
- C
Halved
- D
Unchanged
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