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[12] A solid ball of radius R has a charge density ρ given by ρ=ρ_0 (1- R ) for 0 ≤ r ≤ R. The electric field outside the ball is:

JEE Main 2018 — Physics Electromagnetism

2018mcqhard

[12] A solid ball of radius R\mathrm{R}R has a charge density ρ\rhoρ given by ρ=ρ0(1−rR)\rho=\rho_0\left(1-\frac{r}{R}\right)ρ=ρ0​(1−Rr​) for 0≤r≤R0 \leq r \leq R0≤r≤R. The electric field outside the ball is:

Official previous-year question

Held on 15 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    ρ0R3ε0r2\frac{\rho_0 R^3}{\varepsilon_0 r^2}ε0​r2ρ0​R3​

  2. B

    4ρ0R33ε0r2\frac{4 \rho_0 R^3}{3 \varepsilon_0 r^2}3ε0​r24ρ0​R3​

  3. C

    3ρ0R34ε0r2\frac{3 \rho_0 R^3}{4 \varepsilon_0 r^2}4ε0​r23ρ0​R3​

  4. D

    ρ0R312ε0r2\frac{\rho_0 R^3}{12 \varepsilon_0 r^2}12ε0​r2ρ0​R3​

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