
Let us assume that we connect n(whole number) capacitors in series such that the potential difference across the combination is 1000V. This means the potential difference across each capacitor is
Vcapacitor=n1000V≤300V
n⩾3001000=3.333.
nmin=4
This means we need to connect at least 4 capacitors in series to make sure that the potential across each one is less than 300V.
Ceq=nmC=2μF
4m=2⇒m=8
∴ Minimum no. of capacitors =8×4=32