σ1=−σ2 [due to magnetic force]
E=ϵ0σ=vB
σ=ϵ0vB
JEE Main 2016 — Physics Electromagnetism
Consider a thin metallic sheet perpendicular to the plane of the paper moving with speed v in a uniform magnetic field B going into the plane of the paper (see figure). If charge densities σ1 and σ2 are induced on the left and right surfaces respectively of the sheet, then (ignore fringe effects)

Held on 10 Apr 2016 · Verified 6 Jul 2026.
σ1=2−ϵ0vB,σ2=2ϵ0vB
σ1=ϵ0vB,σ2=−ϵ0vB
σ1=2ϵ0vB,σ2=2−ϵ0vB
σ1=σ2=ϵ0vB
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