
As shown in figure a shunt resistance (S) is connected parallel to the galvanometer to convert it into an ammeter. Let G is the resistance of the galvanometer.
Where G=100Ω and full-scale deflection current is Ig=10mA=10×10−3A
For galvanometer Vg=IgG=10×10−3×10=0.1volt
From the figure, the shunt is parallel to galvanometer
∴VS=Vg⇒ISS=Vg...(1)
For ammeter full-scale deflection current is
IS(=I−Ig)≈10A
∴ from equation (1)
10S=0⋅1⇒S=0⋅01Ω